Pass AJAX Variable to PHP and displaying MySQL results after selection from Dynamic Dropdown

Pass AJAX Variable to PHP and displaying MySQL results after selection
from Dynamic Dropdown

References

Reference NO 1

http://stackoverflow.com/questions/15190059/pass-ajax-variable-to-php-and-displaying-mysql-results-after-selection-from-dyna

Reference NO 2

http://stackoverflow.com/questions/18255652/php-mysql-ajax-not-displaying-data-after-selecting-from-dropdown

Reference NO 3

http://stackoverflow.com/questions/18319013/dynamic-dropdown-selection-fills-in-textfields-from-db-with-ajax

Reference NO 4

http://stackoverflow.com/questions/7623031/how-can-i-display-db-contents-after-selecting-a-dropdown-list-option-using-php

Reference NO 5

http://stackoverflow.com/questions/16753613/dynamically-updating-select-boxes-with-php-mysql-ajax

Reference NO 6

http://stackoverflow.com/questions/15190059/pass-ajax-variable-to-php-and-displaying-mysql-results-after-selection-from-dyna

Reference NO 7

#EANF#

Reference NO 8

#EANF#